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Old 08-03-2020, 08:02 PM   #1
SkunkApe
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Join Date: Dec 2008
Posts: 326
Max Player Belmont final furlong

I'm trying to calculate the final furlong time for Max Player in the Belmont Stakes on 6/20/20. Am I doing this right?

Last two fractional times for the (1-1/8 mile) race were 1:34.46 and 1:46.53

Using .2 seconds per length:

At the mile, #3 max Player was in 5th place.

The # 1 was in 4th place, 1/2 lengths ahead of the #3.

The #10 was in 3rd place, 1-1/2 lengths ahead of the #1.

The #9 was in 2nd place, 1/2 length ahead of the #10.

The #8 was 1st place, 4 lengths ahead of the #9.

So #3 was 6-1/2 lengths off the lead.

Using .2 seconds per length, #3 that's 1.3 seconds off the lead.

Adding 1.3 seconds to the race time of 1:34.46, the #3 ran the mile in 1:35.76.

Am I doing this correctly?

Data from here:

https://www.equibase.com/premium/cha...0&cy=USA&rn=10

Last edited by SkunkApe; 08-03-2020 at 08:03 PM.
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