View Full Version : Calculating number of events to win
jasperson
05-31-2010, 06:22 PM
Say I have a win percentage of 70% is there a way to calculate the maximum number of bets I would have to make before statistically I get a winner? If there is can you give me the formula.
cj's dad
05-31-2010, 06:33 PM
God doesn't win at 70%
only11
05-31-2010, 06:34 PM
God doesn't win at 70%
:lol: :lol: :lol: great line
Overlay
05-31-2010, 06:39 PM
With an established winning probability of 70%, the following is the percentage likelihood of experiencing a losing streak of the lengths indicated:
2 99
3 73.1
4 31.8
5 10.6
6 3.2
7 1.0
8 0.3
9 0.1
(Reference: http://www.financial-spread-betting.com/Losers-winners.html ) (not pertaining specifically to handicapping, but the math should be the same)
Overlay
05-31-2010, 07:50 PM
God doesn't win at 70%
...but, as was noted in the play Boog! that appeared in Sports Illustrated during Boog Powell's heyday, "Only God bats .500."
Overlay
05-31-2010, 08:05 PM
Disregard my previous post / link (#4).
Here is a llink to a calculator that should be more suited to the type of situation under discussion:
http://sbrforum.com/Betting+Tools/Streak+Calculator.aspx
TrifectaMike
05-31-2010, 09:54 PM
Say I have a win percentage of 70% is there a way to calculate the maximum number of bets I would have to make before statistically I get a winner? If there is can you give me the formula.
You can use the following formula:
N = log(1-c)/log(1-p)
N - number of trials
p - win probability
c - confidence level
Example:
p = .7
c = .90 (90% confidence level)
N = log(1-.9)/log(1-.7) = 1,912 run up to 2
90 percent of the time you will have a winner after 2 races.
I believe this is what you want.
Mike
jasperson
06-01-2010, 08:33 AM
Thanks, Mike that is what I was looking for
Jack
vBulletin® v3.8.9, Copyright ©2000-2024, vBulletin Solutions, Inc.