Split Times & Different Distances

[JimmyK]

I just a have a few questions about pace handicapping and I couldn't think of a better forum. How does one compare pace when related to horses whom have ran over different distances.

I am looking for a better ways then I current do it now. Below is a mock layout with times broken down via splits, feet per second (FPS) and miles per hour (MPH). The next race would be for 6 F.

When handicapping different distances I subtract or add .10 fps per 1/2 furlong for the first split, .20 for the second split, and .40 for the third.

5 1/2 F 23.10 46.70 1.04.90
6 F 23.40 47.10 1.11.40
6 1/2 F 23.30 47.00 1.17.88
7 F 23.30 47.10 1.24.30

Broken down
(FPS) (MPH)
5 1/2 F 57.14 55.93 54.39 38.95 38.13 37.08
6 F 56.41 55.70 54.32 38.46 37.98 37.03
6 1/2 F 56.65 55.70 53.44 38.62 37.98 36.44
7 F 56.65 55.46 53.23 38.62 37.13 36.29

Now I only worry about the FPS and I started subtracted or adding accordingly.

5 1/2 F 57.04 55.73 53.99
6 F 56.41 55.70 54.32
6 1/2 F 56.75 55.90 53.84
7 F 56.85 55.86 54.03

I break down the horses in feet per second so that I can place them into a mock race to see if a horse will be stuck outside or possibly squeezed during the race.

If I was to place this back into normal time or MPH this is what it would look like.

Horse 1 ( 5 1/2 F ) 23.14 46.83 1.11.32
Horse 2 ( 6 F ) 23.40 47.10 1.11.40
Horse 3 ( 6 1/2 F ) 23.26 46.87 1.11.39
Horse 4 ( 7 F ) 23.22 46.85 1.11.28

MPH

Horse 1 ( 5 1/2 F ) 38.89 38.00 36.81
Horse 2 ( 6 F ) 38.46 37.98 37.03
Horse 3 ( 6 1/2 F ) 38.69 38.11 36.71
Horse 4 ( 7 F ) 38.76 38.09 36.84

Now I don't normally do this manual as above I have a basic Microsoft works program I just plug in the numbers and distances back and it does it for me.

I was also wondering what time do you subtract when a horse is a length behind and so on.... I current use the basic default of .20 seconds or 1/5 per length does anyone else use a different time that might be more correct especially if a horse is 12 lengths off the lead.


Thanks JimmyK

[lousycapper]

Furlongs times 66; minus lengths behind;
divided by the leaders time; minus 4.5; times 100; round up or down...

Example: 2f x 66 = 132 - 2 lengths = 130

130 / 23.28 seconds = 5.5841924

5.5841924 - 4.5 = 1.0841924

1.0841924 x 100 = 108.41924

Rounded down = 108

This way you will always be dealing with an interger that is easier to handle.

You can add or subtract adjustments for different distances as you see fit.

-L.C.

[Tom]

What would you use for beaten lengths adjsutments?
Or would you just use the horse's time instead of the leader's time?

Thanks

[lousycapper]

Originally posted by Tom@HTR
What would you use for beaten lengths adjsutments?
Or would you just use the horse's time instead of the leader's time?

Thanks

The lengths behind have already been deducted. That's why you use the leader's time.

2f x 66 = 132 - 2 lengths behind = 130

130 / leader's time at the call point.

The only adjustment would be yours: [.1, .2, .4] which would be added to or subtracted from the leader's time at the call point.

The formula with your adjustment for a horse going a longer distance than today's race would be:

2f x 66 = 132

132 - 2 lengths = 130

130 / (23.4 + .1) = 5.5319148

5.5319148 - 4.5 = 1.0319148

1.0319148 x 100 = 103.19148

103.19148 rounded down = 103

Without your adjustment:

105.5555555 rounded up = 106

-L.C.

[lousycapper]

The formula with your adjustment for a horse going a SHORTER distance than today's race would be:

[JimmyK]

Thanks Lousycapper, I like your way I might teak it a little to make the numbers more uniform but I like the idea of giving your horses even split times.

Now all I have to do is figure out how much points to give for other factors such as class jockey trainer etc....

I dont give to many points for certain factors but I do give them that way I can adjust the ratings and see which ones work better.

Thanks again JimmyK

[bobsbet]

Lousycapper:

Back in 2003 you submitted a formula for calculating split times for different distances.

Could you clarify for me the 66 (2Fx66)?? Do you use the 66 for a 4Fand a 6F split calculation??

Also, you show a 4.5 figure in the calculation. Is that also a set figure that is used at all distances?

Thanks